SOLUTION: What is the vertex and the axis of symmetry of the parabola y=x^2+5x-6

Question 681141: What is the vertex and the axis of symmetry of the parabola y=x^2+5x-6
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the vertex and the axis of symmetry of the parabola
y=x^2+5x-6
complete the square:
y=(x^2+5x+25/4)-6-25/4
y=(x+5/2)^2-24/4-25/4
y=(x+5/2)^2-49/4
This is an equation of a parabola that opens upwards.
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
For given equation: y=(x+5/2)^2-49/4
vertex: (-5/2,-49/4)
axis of symmetry: x=-5/2
see graph below:

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