SOLUTION: Find the equation of the parabola.
Focus (5,-2), directrix x=-1
Algebra.Com
Question 679618: Find the equation of the parabola.
Focus (5,-2), directrix x=-1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the equation of the parabola.
Focus (5,-2), directrix x=-1
This is an equation of a parabola that opens rightwards.
Its standard form: (y-k)^2=4p(x-h), (h,x)=(x,y) coordinates of the vertex
For given parabola:
y- coordinate of vertex=-2
x-coordinate of vertex=2 (midpoint of -1 and 5)
vertex:(2,-2)
axis of symmetry: y=-2
p=3 (distance from focus or directrix to vertex on the axis of symmetry)
equation:
(y+2)^2=12(x-2)
RELATED QUESTIONS
Find the vertex, focus, and directrix of the parabola with equation... (answered by Edwin McCravy)
Find the equation of a parabola with focus (2, -3) and directrix x = 5.
(answered by josgarithmetic)
find the equation of the parabola with the given focus and directrix. focus... (answered by josgarithmetic,greenestamps)
find the equation of the parabola that satisfies the given conditions.
Focus: (7,0),... (answered by gonzo)
Find the equation in standard form of the parabola with focus (-1, 9) and directrix x =... (answered by ewatrrr)
Write an equation of the parabola with directrix x=-1 and focus (1,-2). (answered by josgarithmetic)
Find the vertex, focus, and directrix of the parabola given by the equation (x-1)^2 =... (answered by lwsshak3)
Pleasehelpme! 1)find the equation of parabola having focus at(1,1) and directrix... (answered by AnlytcPhil)
Find the vertex, focus and directrix of the parabola ( x -5 )^2 = 8... (answered by josgarithmetic)