SOLUTION: How do you find the center and the foci of the conic section 25x2+50x-9y2-18y-209=0

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Question 675116: How do you find the center and the foci of the conic section 25x2+50x-9y2-18y-209=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Standard Form of an Equation of an Hyperbola opening right and left is:
with C(h,k) and vertices 'a' units right and left of center, 2a the length of the transverse axis
Foci are units right and left of center along y = k
25x2+50x-9y2-18y-209=0 || putting into Standard form
25(x+1)^2 - 9(y+1)^2 - 25 + 9 - 209 = 0
25(x+1)^2 - 9(y+1)^2 = 225

center: C(-1,1)
foci: F(-1+,1) and F(-1-,1)
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