SOLUTION: x^2-6x+25y^2-100y=-84

Algebra.Com
Question 671163: x^2-6x+25y^2-100y=-84
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
conic Forms:
Ellipse is
Hyperbola opening Up and down is:
Hyperbola opening right and left is:
Parabola opening up(a>0) or down(a<0),
Parabola opening right(a>0) or left(a<0),
x^2-6x+25y^2-100y=-84
(x-3)^2 + 25(y-2)^2 = -84 + 9 + 100
(x-3)^2 + 5(y-5)^2 =25
Ellipse
RELATED QUESTIONS

Write x^2+25y^2+6x-100y+9=0 in standard form. Find conic and center (answered by josgarithmetic)
4x^2 + 25y^2 8x + 100y + 4 =... (answered by Alan3354)
find the area bounded by the curve 9x^2 + 25y^2 + 18x - 100y =... (answered by ikleyn)
find the area bounded by the curve 9x^2 + 25y^2 + 18x - 100y =... (answered by ikleyn)
pls help. write hyperbola 25y^2-4x^2+100y+24x-36=0 in standard form center vertices (answered by ewatrrr)
x^2 - 2x +1 - 100y^4 = ? Answer Choices: a) (100y^2 + x - 1)(-100y^2 + x - 1) b)... (answered by greenestamps,Edwin McCravy)
I need to find the center,vertices, and foci of the ellipse... (answered by Edwin McCravy)
4x^2+25y^2-8x+100y+4=0 find the center, vertices and foci of the ellipse (answered by lwsshak3)
x^2+25y^2=25 (answered by Fombitz)