SOLUTION: Help? (x+7)^2+(y-5)^2+4=0

SOLUTION: Help? (x+7)^2+(y-5)^2+4=0

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Question 670767: Help? (x+7)^2+(y-5)^2+4=0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
If you meant

(x+7)^2+(y-5)^2-4 = 0

then you get

(x+7)^2+(y-5)^2 = 4

which is a circle with radius 2 centered at the point (-7, 5)
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