SOLUTION: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400. What

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400. What       Log On


   

Question 663895: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400.
What is the maximum height of the projectile?
When does the projectile hit the ground?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

h(t)=+-16t%5E2+%2B64t%2B400+=+-16%28t+-2%29%5E2+%2B+64+%2B+400+=+-16%28t-2%29%5E2+%2B+464

h(t) = -16%28t-2%29%5E2+%2B+464  V(2,464)max,   464ft is the max height.

 0 = -16(t-2)^2 + 464

(t-2)^2 = 29

 t = 2 ± sqrt(29) ||tossing out negative solution for unit measrure

 t = 7.39 sec, time it takes to hit the ground  



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