SOLUTION: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400. What

Question 663895: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400.
What is the maximum height of the projectile?
When does the projectile hit the ground?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

h(t)=

h(t) =   V(2,464)max,   464ft is the max height.

 0 = -16(t-2)^2 + 464

(t-2)^2 = 29

 t = 2 � sqrt(29) ||tossing out negative solution for unit measrure

 t = 7.39 sec, time it takes to hit the ground  



Donations on my website are appreciated.  Thanks.  ewatrrr

http://math-is-magical.weebly.com/index.html

 

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