Hi,

-x^2+4y^2-6x-48y+139=0

x^2-4y^2+6x+48y =139

 (x+3)^2 - 4(y-6)^2 = 139 + 9 - 144

 (x+3)^2 - 4(y-6)^2 = 4



 C(-3,6), V(-5,6) and (-1,6)

Standard Form of an Equation of an Hyperbola opening right and  left is:

   with C(h,k) and vertices 'a' units right and left of center,   

 

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