SOLUTION: To the nearest foot per second , what is the maxium safe landing speed ?
L = Length s = speed
The equation is L = 0.5s^2 + -4s + 10
How do I complete this if L = 1,500 ?
Algebra.Com
Question 658223: To the nearest foot per second , what is the maxium safe landing speed ?
L = Length s = speed
The equation is L = 0.5s^2 + -4s + 10
How do I complete this if L = 1,500 ?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Take out the L and replace it with 1500.
Solve the quadratic for 
John
My calculator said it, I believe it, that settles it
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