SOLUTION: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6 And: What is the equation of the axis of symmetry of the parabola whose equation

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Question 658044: Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
x = -3
x = 3
x = 0
y = -2
y = 2

Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
-----
Form: (x-h)^2/a^2 + (y-k)/b^2 = 1
h = 6, k = -1 ; a = 6 ; b = 3
Equation:
(x-6)^2/36 + (y+1)/9 = 1
=============================
And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
Vertex is at (-3,2)
Axis of symmetry is x = -3
==============================
Cheers,
Stan H.
===============
x = -3
x = 3
x = 0
y = -2
y = 2

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Standard Form of an Equation of an Ellipse is
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
(0, -1) and (12, -1), C(6,-1) and minor axis of length 6. b = 3


the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry
x = -3 is the Line of Symmetry
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