Hi,

The vertex form of the equation of a parabola is 

y= 5(x-3)^2-6

y = 5(x^2-6x + 9) - 6

y = 5x^2 - 30x + 45 - 6

y = 5x^2 - 30x + 39

Check by completing the square

y = ax^2 + bx + c   ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c

y = 5(x-3)^2 -45 + 39

y = 5(x-3)^2 -6 

RELATED QUESTIONS

The vertex form of the equation of a parabola is y=(x+5)^2+49. What is the standard form... (answered by stanbon,swincher4391)

The vertex of the parabola is y=7(x-3)^2+4 what is the standard form of the equation ?  (answered by ewatrrr)

The vertex form of the equation of a parabola is y = 2(x + 4)2 - 21. 
What is the... (answered by Tatiana_Stebko)

The Standard form of the equation of a parabola is y=x^2-6x+14. What is the vertex form... (answered by ewatrrr)

The vertex form of the equation of a parabola is y=(x+7)^2 + 13. What is the standard... (answered by ewatrrr)

The vertex form of the equation of a parabola is y=(x-4)^2+22. What is the standard form... (answered by lwsshak3)

The vertex form of the equation of a parabola is y = (x + 7)2 + 13. 
What is the... (answered by Fombitz)

The vertex of the equation of the Parabola is y=(x-3)^2+36.
What is the standard form of  (answered by Boreal)

 Write the equation of a parabola in standard form. Give the coordinates of the vertex.

 (answered by Fombitz)