SOLUTION: Convert this general equation of a hyperbola to standard form. -4x^2+y^2-8x-12y+36=0

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Question 639080: Convert this general equation of a hyperbola to standard form.
-4x^2+y^2-8x-12y+36=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Convert this general equation of a hyperbola to standard form.
-4x^2+y^2-8x-12y+36=0
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-4x^2+y^2-8x-12y+36=0
-4x^2-8x+y^2-12y+36=0
complete the square
-4(x^2+2x+1)+(y^2-12y+36)=-36-4+36
-4(x+1)^2+(y-6)^2=-4
divide by -4
standard form of equation:%28x%2B1%29%5E2-%28y-6%29%5E2%2F4=1
This is an equation of a hyperbola with horizontal transverse axis (x-term leading)
Its standard generic form: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
center: (-1,6)
a^2=1
b^2=4