SOLUTION: Find vertex and focus of parabola 4y = x squared

SOLUTION: Find vertex and focus of parabola 4y = x squared - 12x + 52 How do you do this one?

Question 636912: Find vertex and focus of parabola
4y = x squared - 12x + 52
How do you do this one?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find vertex and focus of parabola
4y = x squared - 12x + 52
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Complete the square:
4y = x^2-12x+36 + 16
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y = (1/4)(x-6)^2 + 4
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Vertex: (6,4)
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To find the focus:
4p = 1/4
p = 1/16
----
Focus is 1/16 above the vertex:
Focus: (6 , 4+(1/16)) or (6,67/16)
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Cheers,
Stan H.
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