SOLUTION: (x+5)^2=+32(y+1)

Question 636682: (x+5)^2=+32(y+1)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
(x+5)^2=+32(y+1)
This is an equation of a parabola that opens upwards.
Its form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.
For given parabola:
vertex: (-5,-1)
axis of symmetry: x=-5
4p=32
p=8
focus: (-5,-1+8)=(-5,7)
directrix: y=-9

RELATED QUESTIONS
x^5/2=32 (answered by lwsshak3)

2x+y-1=0... (answered by greenestamps)

(y+3)5/2=32 (answered by checkley71)

Simplify square root (32 x^5... (answered by checkley77)

32^x-1... (answered by Alan3354)

Suppose x and y vary inversely, and x = 5 when y = 1.6 1. Write a function that... (answered by uday1435,vleith)

Suppose x and y vary inversely, and x = 5 when y = 1.6 1. Write a function that... (answered by Mathtut)

... (answered by cira554)

4^(x+3)=32{2^(x+y)} (answered by Fombitz)