SOLUTION: Write the equation of the circle in standard form.��Find the center, radius, intercepts, and graph the circle. x^2+y^2+8x+2y+8=0 I am having trouble with the steps involved.

Question 636257: Write the equation of the circle in standard form.��Find the center, radius, intercepts, and graph the
circle.
x^2+y^2+8x+2y+8=0
I am having trouble with the steps involved.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the
circle.
x^2+y^2+8x+2y+8=0
**
Standard form of equation for a circle: , (h,k)=(x,y) coordinates of center, r=radius.
x^2+y^2+8x+2y+8=0
complete the square
x^2+8x+y^2+2y+8=0
(x^2+8x+16)+(y^2+2y+1)=-8+16+1
Equation:

..
r^2=9
radius=3
..
center:(-4,-1)
..
x-intercepts:
set y=0
(x+4)^2+1=9
(x+4)^2=8
x+4=�√8
x=-4�√8
x≈-6.83
or
x≈-1.17
..
See graph below:
y=�(9-(x+4)^2)^.5-1

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