SOLUTION: Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)).
Question 636108: Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)). Found 2 solutions by ewatrrr, lwsshak3:Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
Write the equation of a circle that has the center on the x-axis,
a radius of 1, and passes through the point
(,)
(x,0)
D = = 1 , -x =± , x =
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website! Write the equation of a circle that has the center on the x-axis, a radius of 1, and passes through the point (((square root of 2)/2),((square root of 2)/2)).
**
Equation of a circle: , (h,k)=(x,y) coordinates of center, r=radius
For given circle:
r^2=1
r=1
k==0
equation:
(x-h)^2+y^2=1
solve for h using coordinates of given point (√2/2, √2/2)
(√2/2-h)^2+(√2/2)^2=1
2/4-√2h+h^2+2/4=1
h^2-√2h+1=1
h^2-√2h=0
h(h-√2)=0
h=0 (reject, does not check)
h=√2
Equation: (x-√2)^2+y^2=1