SOLUTION: Find the vertices,asymptotes, and the foci of the hyperbola. y^(2)-4x^(2)-6y-32x-59=0

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Question 633543: Find the vertices,asymptotes, and the foci of the hyperbola.
y^(2)-4x^(2)-6y-32x-59=0

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Re TY, Yes! Good Work!
y^(2)-4x^(2)-6y-32x-59=00 ⇒ (y-3)^2 - 4(x+4)^2 = 4
C(-4,3)
V(-4, 5) and V(-4,1)
Foci (-4, 3 ±)
Asymptotes:
y-3 = 2(x +4) y = 2x +11
and y-3 = -2(x+4) y = -2x -5
Standard Form of an Equation of an Hyperbola opening up and down is:
with C(h,k) and vertices 'b' units up and down from center, 2b the length of the transverse axis
Foci units units up and down from center, along x = h
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a

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