SOLUTION: what is the radius of the circle defined by the equation x^2+y^2-4x+18y+81=0 ?
Algebra
.Com
Question 629592
:
what is the radius of the circle defined by the equation x^2+y^2-4x+18y+81=0 ?
Answer by
ewatrrr(24785)
(
Show Source
): You can
put this solution on YOUR website!
Hi,
x^2+y^2-4x+18y+81=0
(x-2)^2 + (y+9)^2 - 4 - 81 +81 = 0
r = 2
RELATED QUESTIONS
Find the center and radius of the circle defined by the equation: X^2+Y^2+4X-8Y+13=0
(answered by
josgarithmetic
)
Write an equation of the circle equation in standard form. Find the center, radius,...
(answered by
solver91311
)
find the radius of the circle defined by the equation:...
(answered by
Fombitz,ewatrrr
)
Find the radius of the circle defined by the equation:...
(answered by
ewatrrr,MathLover1
)
write the equation of the circle in standard form. find the center, radius, intercepts,...
(answered by
stanbon
)
Find the radius of a circle defined by the equation:...
(answered by
solver91311
)
The radius of a circle defined by...
(answered by
solver91311
)
Find the radius of the circle defined by the equation x^2+y^2+12x+8y+16=0 Is kinda...
(answered by
ewatrrr
)
classify the conic section defined by the equation 4x^2+9x^2-8x-18y-23=0 mulitple choice
(answered by
lwsshak3
)