Hi,

Note: Standard Form of an Equation of a Circle is  

where Pt(h,k) is the center and r is the radius



Write an equation of the line tangent to the given circle at the given point.

 (-4,6)  || Center of the circle is (0,0)

(-4,6)

(0,0) m = 6/-4 Green Line has slope m = -3/2, 

the Line Tangent at (-4,6) would be perpendicular to the Green with m = 2/3

 y = (2/3)x + b

 6 = -8/3 + b,  

  26/3 = b ,     y = (2/3)x + 26/3



 

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