SOLUTION: Graph the equation (I don't know how to find them) {{{ 2x^2+50y^2=50 }}} Identify the vertices of the ellipse. Identify the co-vertices of the elli

Question 624382: Graph the equation (I don't know how to find them)

Identify the vertices of the ellipse.
Identify the co-vertices of the ellipse.
Identify the foci of the ellipse.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Graph the equation (I don't know how to find them)
2x^2+50y^2=50
Identify the vertices of the ellipse.
Identify the co-vertices of the ellipse.
Identify the foci of the ellipse.
**
2x^2+50y^2=50
x^2/25+y^2=1
This is an equation of an ellipse with horizontal major axis with center at the origin (0,0)
Its standard form of equation: x^2/a^2+y^2/b^2=1, a>b
center:(0,0)
a^2=25
a=5
Vertices: (0�a,0)=(0�5,0)=(-5,0) and (5,0)
..
b^2=1
b=1
co-vertices: (0,0�b)=(0,0�1)=(0,-1) and (0,1)
..
c^2=a^2-b^2=25-1=24
c=√24≈4.9
Foci: (0�c,0)=(0�4.9,0)=(-4.9,0) and (4.9,0)
see graph below:
y=�(1-x^2/25)^.5

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