SOLUTION: Parabola questions are the hardest can someone help me figure this out show steps please. The parabola given by the equation y=-x^2+8 x-8 has its vertex at (h,k) for: h= an

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Question 622707: Parabola questions are the hardest can someone help me figure this out show steps please.

The parabola given by the equation y=-x^2+8 x-8 has its vertex at (h,k) for:
h=
and
k=

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
y = -x^2+ 8x- 8 |putting into Vertex form by completing the Square
y = -(x-4)^2 + 16 - 8
y = -(x-4)^2 + 8 V(4,8) (h is 4 and k is 8)
Note: In general: y = ax^2 + bx + c
If you need a shortcut on this: y = -x^2+ 8x- 8, (a = -1, b = 8 and c = -8)
In general: y = ax^2 + bx + c .... going to y = a(x-h)^2 + k ... following is true



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