SOLUTION: I need help with this parabola question it is hard for me to find the vertex of this question. Find the vertex of the parabola y = 12 x + 4 - x^2. Enter your answer as a point

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need help with this parabola question it is hard for me to find the vertex of this question. Find the vertex of the parabola y = 12 x + 4 - x^2. Enter your answer as a point      Log On


   

Question 622703: I need help with this parabola question it is hard for me to find the vertex of this question.

Find the vertex of the parabola y = 12 x + 4 - x^2. Enter your answer as a point (h,k), including the parentheses.
The vertex is at the point:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

y = 12x + 4 - x^2.    |putting into the general order...

 y = ax^2 + bx + 4 

y = -x^2 + 12x + 4    |putting into Vertex Form y+=+a%28x-h%29%5E2+%2B+k by completing the Square

y = -(x-6)^2 + 36 + 4

y = -(x-6)^2 + 40   V(6,40)

If You are having difficulty completing the Square, this short-cut may help:

  h+=+-b%2F2a+=+-12%2F-2+=+6

  k+=+c+-+%28b%5E2%2F4a%29+=+4+-144%2F-4+=+40