SOLUTION: determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0

Algebra.Com
Question 620834: determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
x^2+4y^2+12x-32y = 96
(x+6)^2 + (y-16)^2 = 96 - 36 - 256 = 196
a circle C(-6,16) and r = 14
RELATED QUESTIONS

identify the equation by the type of conic it graphs to be X^2 -4X -4Y^2 +32Y =64 (answered by Alan3354)
what is the center of this ellipse?... (answered by ewatrrr)
Determine the type of curve represented by the equation... (answered by lwsshak3)
{{{x^2-4y^2+2x-32y-67=0}}} I need this equation in y form pleas and thank u and please... (answered by Edwin McCravy)
what is the center of... (answered by lwsshak3)
Find the center radius form of 4x^2+4x+4y^2+32y-79=0 (answered by Fombitz)
Write the equation of the parabola with the shape as f(x)=-2x^2, but with the vertex... (answered by lwsshak3)
find the radius of the circle defined by the equation:... (answered by Fombitz,ewatrrr)
Graph the line represented by... (answered by Nate)