SOLUTION: determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0
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Question 620834
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determine the shape of the graph represented by this equation: x^2+4y^2+12x-32y+96=0
Answer by
ewatrrr(24785)
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Hi,
x^2+4y^2+12x-32y = 96
(x+6)^2 + (y-16)^2 = 96 - 36 - 256 = 196
a circle C(-6,16) and r = 14
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