SOLUTION: A.Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. 2x2 – 7y2 + x – y – 2 = 0 B.Classify the graph of the equation as a circle, a para

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A.Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. 2x2 – 7y2 + x – y – 2 = 0 B.Classify the graph of the equation as a circle, a para      Log On


   

Question 620563:
A.Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola.
2x2 – 7y2 + x – y – 2 = 0
B.Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola.
8x2 – 4y2 – 4x – y + 8 = 0
Answer by solver91311(24713) About Me  (Show Source):
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Has term AND term, therfore NOT a parabola

Coefficients on and are different, therefore NOT a circle

Coefficients on and have different signs, therefore NOT an ellipse

Therefore hyperbola.

John

My calculator said it, I believe it, that settles it
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