SOLUTION: (x+3)^2/7^2-(y-4)^2/5^2=1 which direction does the hyperbola go?

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Question 620174: (x+3)^2/7^2-(y-4)^2/5^2=1 which direction does the hyperbola go?
Found 2 solutions by solver91311, ewatrrr:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Since there is no term, the transverse axis (the one that goes through the vertices and foci as opposed to the conjugate axis that is perpendicular to the transverse axis) is either parallel to the -axis or to the -axis.

The variable in the positive term identifies the axis parallel to the transverse axis.

John

My calculator said it, I believe it, that settles it
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%28x%2B3%29%5E2%2F7%5E2-%28y-4%29%5E2%2F5%5E2=1+ Opens right and left along y = 4

  C(-3,4) and V(-10,4) & V(4,4)

Standard Form of an Equation of an Hyperbola opening right and  left is:

  %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 

where Pt(h,k) is a center  with vertices 'a' units right and left of center 

and foci sqrt%28a%5E2%2Bb%5E2%29units from center along y = k