SOLUTION: I have the following equation: I need to identify the vertices and foci of the hyperbola. I also need to show my work. (y+5)^2/36 - (x+2)^2/25 =1 thank you

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Question 619477: I have the following equation: I need to identify the vertices and foci of the hyperbola. I also need to show my work.
(y+5)^2/36 - (x+2)^2/25 =1
thank you

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Note:Standard Form of an Equation of an Hyperbola opening up and down is:
where Pt(h,k) is a center with vertices 'b' units up and down from center and foci from center along x = h
(y+5)^2/36 - (x+2)^2/25 =1 C(-5,-2) V(,-5,-8) & V(-5,4), F(-5, -2±)
See below descriptions of various conics
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius

Standard Form of an Equation of an Ellipse is where Pt(h,k) is the center. (a positioned to correspond with major axis)
a and b are the respective vertices distances from center and ±are the foci distances from center: a > b
Standard Form of an Equation of an Hyperbola opening right and left is:
where Pt(h,k) is a center with vertices 'a' units right and left of center and foci {{sqrt(a^2+b^2) from center along y = k.
Standard Form of an Equation of an Hyperbola opening up and down is:
where Pt(h,k) is a center with vertices 'b' units up and down from center along x = h.
the vertex form of a parabola opening up or down, where(h,k) is the vertex.
The standard form is , where the focus is (h,k + p)
the vertex form of a parabola opening right or left, where(h,k) is the vertex.
The standard form is , where the focus is (h +p,k )

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