SOLUTION: How do you find the center, vertices, and the foci of the ellipse? (y-5)^2/25+(x+1)^2/16=1 Or 36x^2+9y^2+72x-36y+36=0

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Question 618493: How do you find the center, vertices, and the foci of the ellipse?
(y-5)^2/25+(x+1)^2/16=1
Or
36x^2+9y^2+72x-36y+36=0

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Standard Form of an Equation of an Ellipse is where Pt(h,k) is the center. (a positioned to correspond with major axis)
a and b are the respective vertices distances from center and ±are the foci distances from center: a > b

C(-1,5) Vertices( -5,5)(3,5) and (-1,10)(-1,0)
± = ± 3 F( 2,5) &(-4,5)

See below descriptions of various conics
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius

Standard Form of an Equation of an Ellipse is where Pt(h,k) is the center. (a positioned to correspond with major axis)
a and b are the respective vertices distances from center and ±are the foci distances from center: a > b
Standard Form of an Equation of an Hyperbola opening right and left is:
where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
where Pt(h,k) is a center with vertices 'b' units up and down from center.
the vertex form of a parabola opening up or down, where(h,k) is the vertex.
The standard form is , where the focus is (h,k + p)
the vertex form of a parabola opening right or left, where(h,k) is the vertex.
The standard form is , where the focus is (h +p,k )
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