SOLUTION: (x+3)^2/16-y^2/9=1 conic center foci graph

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Question 613637: (x+3)^2/16-y^2/9=1
conic
center
foci
graph

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,

Hyperbola opening right and left, C(-3,0) Vertices(-7,0) & (1,0)
sqrt(16+9) = sqrt(25)= 5 Foci(-8,0) and (2,0)


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