SOLUTION: Need help on writing the standard form of the equation:{{{ y^2-x+2y+3=0}}} I tryed it out by completing the square this is what I done: {{{ y^2-x+2y+3=0}}} {{{ y^2+2y-x+3=0}}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Need help on writing the standard form of the equation:{{{ y^2-x+2y+3=0}}} I tryed it out by completing the square this is what I done: {{{ y^2-x+2y+3=0}}} {{{ y^2+2y-x+3=0}}}       Log On


   

Question 612997: Need help on writing the standard form of the equation:+y%5E2-x%2B2y%2B3=0
I tryed it out by completing the square this is what I done:
+y%5E2-x%2B2y%2B3=0
+y%5E2%2B2y-x%2B3=0 grouped the y terms together
y%5E2%2B2y%2B1=+x-3+%2B1 divided 2 by -2 and squared it, moved x+3 to the right and added 1 to both sides.
%28y%2B1%29%5E2+=+x-2+ that's the last part I got. Am I on the right track? I think it's supposed to be a parabola.
Please show your steps on how to get the answer.
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Need help on writing the standard form of the equation:+y%5E2-x%2B2y%2B3=0
I tryed it out by completing the square this is what I done:
+y%5E2-x%2B2y%2B3=0
+y%5E2%2B2y-x%2B3=0 grouped the y terms together
y%5E2%2B2y%2B1=+x-3+%2B1 divided 2 by -2 and squared it, moved x+3 to the right and added 1 to both sides.
%28y%2B1%29%5E2+=+x-2+ that's the last part I got. Am I on the right track? I think it's supposed to be a parabola.
Please show your steps on how to get the answer.
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One more step
%28y%2B1%29%5E2+%2B+2+=+x+

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

+y%5E2-x%2B2y%2B3=0 

%28y%2B1%29%5E2+=+x-2+  Yes!!!

%28y%2B1%29%5E2+%2B2+=+x+

 Parabola opening right, Vertex (2,-1)