# SOLUTION: How do you find the vertex, focus and directrix of a parabola 1/2y^2+18x=0

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 612348: How do you find the vertex, focus and directrix of a parabola 1/2y^2+18x=0Answer by lwsshak3(6761)   (Show Source): You can put this solution on YOUR website!How do you find the vertex, focus and directrix of a parabola 1/2y^2+18x=0 rewrite equation into standard form: (y-k)^2=-4p(x-h) y^2/2=-18x y^2=-36x This is an equation of a parabola that opens leftwards. vertex:(0,0) axis of symmetry: x-axis or y=0 4p=36 p=9 focus(0,-9) (p distance left of vertex on the axis of symmetry) directrix:(0,9) (p distance right of vertex on the axis of symmetry)