SOLUTION: identify the focus and the directrix of each parabola -5y^2 - x =0
Algebra.Com
Question 611870: identify the focus and the directrix of each parabola -5y^2 - x =0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
identify the focus and the directrix of each parabola
-5y^2 - x =0
5y^2=-x
y^2=-x/5
This is a parabola that opens leftwards
Its standard form of equation: ((y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
For given parabola:
vertex:(0,0)
axis of symmetry: (x-axis) or y=0
4p=1/5
p=1/20
focus:(1/20,0) (p units from vertex on axis of symmetry)
Directrix: x=-1/20 (p units from vertex on axis of symmetry)
RELATED QUESTIONS
Identify the focus and the directrix for the following parabola:... (answered by lwsshak3)
graph the parabola and identify the vertex, focus, directrix:... (answered by lwsshak3)
Identify the vertex, focus and directrix of the parabola with the equation... (answered by ewatrrr,lwsshak3)
Identify the vertex, focus, and directrix of the parabola with the equation... (answered by ewatrrr)
Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)
Identify the focus, directrix, and axis of symmetry then graph the parabola... (answered by lwsshak3)
Draw the parabola. Identify the focus and directrix and show them on the graph.... (answered by lwsshak3)
parabola,x^2 +6x -y +11 =0
find the vertex,focus and directrix of the... (answered by lwsshak3)
Identify the focus and directrix of the parabola y=-15x^2, 6x^2-3y=0,... (answered by ewatrrr)