SOLUTION: Graph: (x+3)^2+(y+1)^2=4 (y+2)^2=4(4)(1)(x-1) (x+2)^2/9-(y-3)^2/4=1 (x-2)^2/4+(y+3)^2/9=1 Thanks soo much

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Question 611284: Graph:

(x+3)^2+(y+1)^2=4


(y+2)^2=4(4)(1)(x-1)

(x+2)^2/9-(y-3)^2/4=1

(x-2)^2/4+(y+3)^2/9=1

Thanks soo much

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
(x+3)^2+(y+1)^2=4 ||Circle with C(-3,-1) and radius of 2

(y+2)^2=16px-1) ||The standard form is , where the focus is (h,k + p)
parabola opening to the right, C(1,-2) and focus(5,-2) 4p=16, p = 4

(x+2)^2/9-(y-3)^2/4=1
Standard Form of an Equation of an Hyperbola is opening right or left
where Pt(h,k) is a center with vertices 'a' units right and left of center.
Asymptotes passing thru the center with slope = ± b/a
foci being ± sqrt(a^2 + b^2) from center along axis of symmetry y = b

||Ellipse with C(2,-3) V(2,0) and V(2,-6)


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