Hi,
what do the graphs for y=1/12(x)^2 and x = -1/4(y)^2 look like ||Assume the + was an = sign
the vertex form of a parabola opening up or down,
where(h,k) is the vertex.The standard form is
, where the focus is (h,k + p)
opens Upward as a = 1/12 > 0 Green
the vertex form of a parabola opening right or left,
where(h,k) is the vertex.The standard form is
, where the focus is (h +p,k )
opens to the LEFT as a = -1/4 < 0
