Hi, 

what do the graphs for y=1/12(x)^2 and x = -1/4(y)^2 look like   ||Assume the + was an = sign

the vertex form of a parabola opening up or down,  where(h,k) is the vertex.The standard form is , where  the focus is (h,k + p)

 opens Upward as a = 1/12 > 0   Green

the vertex form of a parabola opening right or left,  where(h,k) is the vertex.The standard form is , where  the focus is (h +p,k )

 opens to the LEFT as a = -1/4 < 0



 

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