SOLUTION: What are the directrices of the hyperbola given by the equation (y^2/49)-(x^2/9)=1?
Algebra.Com
Question 610057: What are the directrices of the hyperbola given by the equation (y^2/49)-(x^2/9)=1?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What are the directrices of the hyperbola given by the equation
(y^2/49)-(x^2/9)=1?
**
This is an equation of a hyperbola with vertical transverse axis.
Its standard form: (y-k)^2/a^2-(x-h)^2=1, (h,k)=(x,y) coordinates of center.
For given equation: (y^2/49)-(x^2/9)=1
center: (0,0)
a^2=49
a=√49=7
b^2=9
c^2=a^2+b^2=49+9=58
c=√58≈7.6
..
eccentricity, e=c/a=√58/7
directrices=±a/e=±a^2/c=±49/√58≈±6.43
RELATED QUESTIONS
What are the vertices of the hyperbola given by the equation... (answered by KMST)
What are the foci of the hyperbola given by the equation (x+10)^2/25 - (y+1)^2/9 = 1? (answered by Edwin McCravy)
What is the center of the hyperbola described by the following equation... (answered by MathLover1)
What are the asymptotes of the hyperbola given by the equation... (answered by lwsshak3)
What are the lengths of the transverse and conjugate axes of the hyperbola given by the... (answered by lwsshak3)
What is the general conic form equation of the hyperbola?
(y+1)^2/49 -... (answered by lwsshak3)
What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?
(answered by Edwin McCravy)
What is the eccentricity of the hyperbola given by the equation... (answered by lwsshak3)
What are the vertices of the hyperbola x^2/9 - y^2/4... (answered by Theo)