Write the equation in standard form for the conic section.
An ellipse centered at (3,2) with vertices at (9,2) and (-3,2)and co vertices at (3,5) and (3,-1)
I think you need a more graphical approach than just a word explanation.
Plot the points and draw the graph:
Since the ellipse is this way "" and not this way "", its equation is:
+ = 1
[Had it been the other way the "a" and "b" would be switched. In an
ellipse "a" is always larger than "b", but not necessarily in a hyperbola!]
(h,k) = the center = (3,2), "a" = semi-major-axis, sometimes called
"the long radius" and "b" = the semi-minor-axis, sometimes called
"the short radius".
draw the semi-major and semi-minor axes:
The red line is the semi-major axis and the green line is the semi-minor
axis.
Count the number of units that the red and green lines are in
length and you'll get a = 6 and b = 3. Therefore the equation
+ = 1
becomes:
+ = 1
or
+ = 1
Edwin