SOLUTION: Foci: (-6,0), (6,0); y-intercepts: -5 and 5

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Question 607081: Foci: (-6,0), (6,0); y-intercepts: -5 and 5
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Ellipse:
where Pt(h,k) is the center.
a and b are the respective vertices distances from center and ±are the foci distances from center
Foci: (-6,0) and (6,0) , and major axis is along y = 0
6= a = sqrt(61)
y-intercept: 5 and -5


See below descriptions of various conics
Standard Form of an Equation of a Circle is
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is where Pt(h,k) is the center.
a and b are the respective vertices distances from center and ±are the foci distances from center
Standard Form of an Equation of an Hyperbola opening right and left is:
where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
where Pt(h,k) is a center with vertices 'b' units up and down from center.
the vertex form of a parabola opening up or down, where(h,k) is the vertex.
The standard form is , where the focus is (h,k + p)
the vertex form of a parabola opening right or left, where(h,k) is the vertex.
The standard form is , where the focus is (h +p,k )

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