Hi,

Write the conic in standard form:

y^2-10y-4x+57=0

(y^2-10y + 25) -25 -4x +57 = 0

(y-5)^2 +32 = 4x

 x = (1/4)(y-5)^2 +8

Standard Form:

 (y-5)^2 = 4(x-8)



the vertex form of a parabola opening right or left,  where(h,k) is the vertex.

The standard form is , where  the focus is (h +p,k )



 

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