SOLUTION: Write the conic in standard form. y^2-x^2+2y-14x-57=0

Question 606756: Write the conic in standard form.
y^2-x^2+2y-14x-57=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Write the conic in standard form.
y^2-x^2+2y-14x-57=0
complete the square
(y^2+2y+1)-(x^2+14x+49)=57+1-49
(y+1)^2-(x+7)^2=9
(y+1)^2/9-(x+7)^2/9=1
This is an equation of a hyperbola with vertical transverse axis.
Its standard form of equation: (y-k)^2/a^2-(x-h)^2=1, (h,k)=(x,y) coordinates of center.
For given equation: (y+1)^2/9-(x+7)^2/9=1
center: (-7,-1)
a^2=9
b^2=9
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