SOLUTION: What are the locations of the vertices: (x-4)^2/25 - (y-7)^2/9 = 1

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Question 606198: What are the locations of the vertices: (x-4)^2/25 - (y-7)^2/9 = 1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What are the locations of the vertices: (x-4)^2/25 - (y-7)^2/9 = 1
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Center at (4,7)
a = sqrt(25) = 5
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Vertices:
(4-5,7) = (-1,7)
(4+5,7) = (9,7)
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cheers,
Stan H.