SOLUTION: The problem is y^2-6y+16x+25=0. I have to find the vertex, the focus, the directrix and the axis.

Question 605452: The problem is y^2-6y+16x+25=0. I have to find the vertex, the focus, the directrix and the axis.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The problem is y^2-6y+16x+25=0.
I have to find the vertex, the focus, the directrix and the axis.
-----------------------------
Rearrange:
16x = -y^2+6y-25
16x = -(y^2-6y+25)
16x = -(y^2-6y+9)-25+9
--------
x = (-1/16)(y-3)^2 +(9/16)
That is a parabola opening to the left:
k = 3 ; h = 9/16
4p = -1/16
p = -1/64
-----------------
Vertex: (9/16 , 3)
Axis: y = 3
Focus: (9/16-1/64,3) = (35/64 , 3)
Directrix: x = 9/16+1/64 = 37/64
=========================================
Cheers,
Stan H.
=================

RELATED QUESTIONS
find the vertex,focus,axis and directrix of the equation... (answered by lwsshak3)

PARABOLA: what's the vertex, focus, directrix, latus rectum and graph of the... (answered by solver91311)

I need to find the vertex, focus, directrix and axis of symmetry of the parabola:... (answered by lynnlo)

What is the focus, vertex and directrix of the parabola... (answered by lwsshak3)

What is the focus, vertex, axis of symmetry and directrix of the parabola equation... (answered by lwsshak3)

Find the vertex, focus and directrix of the parabola, {{{ y^2-10y+4x+25=0 }}} (answered by josgarithmetic)

What is the vertex, axis of symmetry, focus, and directrix of the parabola... (answered by MathLover1)

Find the focus, directrix, vertex and axis of symmetry x^2=1/8... (answered by MathLover1)

The question is : Identify the vertex, focus, axis of symmetry, and directrix for the... (answered by stanbon)