SOLUTION: I need to find the vertex, focus, directrix and axis of symmetry of the parabola: x^2-4x-2y = 0

SOLUTION: I need to find the vertex, focus, directrix and axis of symmetry of the parabola: x^2-4x-2y = 0

Algebra.Com

Question 603326: I need to find the vertex, focus, directrix and axis of symmetry of the parabola: x^2-4x-2y = 0
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
x^2-4x-2y=0
vertex(2,-2)
focus(2-3/2
axis 1/2
directrix y=- 5/2
RELATED QUESTIONS
Please help me solve this equation Find the Parabola properties and graph x^2+4x+2y=0 (answered by rothauserc)

find the properties of parabola: y^2=x vertex: axis of symmetry focus directrix... (answered by josgarithmetic)

find the properties of parabola: x^2-y=0 vertex: axis of symmetry focus directrix... (answered by stanbon)

Identify the focus, directrix, and axis of symmetry then graph the parabola... (answered by lwsshak3)

name the direction vertex Axis of symmetry focus directrix of the parabola y= -1/4x^2 (answered by lwsshak3)

Please help me find the axis of symmetry, the focus, directrix and vertex of the... (answered by stanbon)

How do you find the vertex, focus, directrix, and axis of symmetry of the parabola?... (answered by ewatrrr,lwsshak3,John10)

Find a) vertex, b ) focus, c) directrix, d) symmetry axis, e) focal distance of the... (answered by lwsshak3)

What is the vertex, axis of symmetry, focus, and directrix of the parabola... (answered by MathLover1)