SOLUTION: the equation of a parabola with the given focus and directrix F(0,-5), y=5

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 600232: the equation of a parabola with the given focus and directrix F(0,-5), y=5Answer by lwsshak3(6481)   (Show Source): You can put this solution on YOUR website!the equation of a parabola with the given focus and directrix F(0,-5), y=5 This is an equation of a parabola that opens downwards. (directrix at y=5, shows this) Its standard form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of vertex. For given equation: axis of symmetry: x=0 x-coordinate of vertex=0 (from focus) y-coordinate of vertex=0 (half way between -5 and 5 on the axis of symmetry p=5 (distance to vertex from focus or directrix on the axis of symmetry 4p=20 equation of given parabola: x^2=20y