# SOLUTION: write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13      Log On

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 597194: write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13Answer by stanbon(57395)   (Show Source): You can put this solution on YOUR website!write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13 ----- x^2 + (y^2+14y+49) = -13+49 ---- (x-0)^2 + (y+7)^2 = 36 --- Draw a circle with center at (0,-7) and radius = sqrt(36) = 6 ============= cheers, Stan H. ==================