# SOLUTION: The vertex of the parabola below is at the point (3, 2) and the point (4, 6) is on the parabola. What is the equation of the parabola? a. x = 6(y - 3)^2 + 2 b. y = 4(x - 3)^2 +

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: The vertex of the parabola below is at the point (3, 2) and the point (4, 6) is on the parabola. What is the equation of the parabola? a. x = 6(y - 3)^2 + 2 b. y = 4(x - 3)^2 +      Log On

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 594385: The vertex of the parabola below is at the point (3, 2) and the point (4, 6) is on the parabola. What is the equation of the parabola? a. x = 6(y - 3)^2 + 2 b. y = 4(x - 3)^2 + 2 c. y = 2(x - 2)^2 + 3 d. y = 4(x + 3)^2 - 2 ..Please !!!Answer by lwsshak3(6509)   (Show Source): You can put this solution on YOUR website!The vertex of the parabola below is at the point (3, 2) and the point (4, 6) is on the parabola. What is the equation of the parabola? a. x = 6(y - 3)^2 + 2 b. y = 4(x - 3)^2 + 2 c. y = 2(x - 2)^2 + 3 d. y = 4(x + 3)^2 - 2 ** Standard form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, A is a multiplier that affects the slope or steepness of the curve. y=A(x-h)^2+k plug in vertex coordinates (3,2) y=A(x-3)^2+2 plug in coordinates of given point (4,6) 6=A(4-3)^2+2 6=A(1)^2+2 6=A+2 A=4 Equation: y=4(x-3)^2+2 b. is the answer