SOLUTION: I needed to find the vertex of this parabola: y = -x^2 - 3x - 2 so what I did was: 0 = -x^2 - 3x - 2 x = -1, x = -2 Two x-intercepts: (-1, 0) and (-2, 0) y = -0^2 -

Question 58609: I needed to find the vertex of this parabola: y = -x^2 - 3x - 2
so what I did was:
0 = -x^2 - 3x - 2
x = -1, x = -2
Two x-intercepts: (-1, 0) and (-2, 0)
y = -0^2 - 3(0) - 2 = -2
One y-intercept: (0, -2)
x = 1/2(-1 - 2) = -3/2
y = -3/2
y = -3/2 - 2)-3/2) - 2 = 1.5
Vertex is -3/2, 1.5
Is this correct?

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Find the vertex of this parabola: y = -x^2 - 3x - 2
You got the x value right, but you're doing it in such a way that if you cannot factor it, you won't find it. Therefore, I'm going to show you the sure fire way of finding the x value of the vertex, no matter what and then we'll see what went wrong for the y-value:
The formula for finding the x-value of the vertex of a parabola is , for a quadratic equation written in standard form:
Your a=-1, b=-3, and c=-2

Substitute that value into the equation for x and solve for y:

The vertex is: (x,y)=(-1.5,.25)
Happy Calculating!!!
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