SOLUTION: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?

SOLUTION: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?

Algebra.Com

Question 584622: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
(x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?
This is an equation of a circle with center at (3,-1) and radius=2
So, with a compass set 2 units apart, place the pointer on point (3,-1) and draw a circle with a radius=2.

RELATED QUESTIONS
Can someone help me with the following graph problem? I need to give the coordinates... (answered by stanbon)

y= (x+4)-(x+1) the (brackets) are supposed to be the absolute value bar lines i... (answered by stanbon)

My problem...y=x^2+5 . I am supposed to graph this equation... so I make a function... (answered by Alan3354)

Can you please help me with these problems. I need to know how to work it out, not just... (answered by stanbon)

Please help. I am so lost I have to pass this final. I have a few questions. 1. Graph... (answered by stanbon)

Let point A be a point on the circle whose equation is (x - 3)^2 + (y + 4)^2 = 50. How... (answered by ikleyn,Edwin McCravy)

(x+2)^2 + (y-3)^2=49 i am supposed to identify the conic. i think its a circle is that... (answered by Fombitz)

Graph the system of inequalities. y >_ -4 x >_ 5 OK Do i just put a dot on the y... (answered by stanbon)