SOLUTION: Find the vertex, focus, and directrix of the parabola. x^2=2y
Algebra.Com
Question 578940: Find the vertex, focus, and directrix of the parabola. x^2=2y
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, focus, and directrix of the parabola. x^2=2y
**
Standard form of an equation for a parabola that opens upwards: (x-h)^2=4p(y-k), with (h,k) being the coordinates of the vertex
..
For given equation, x^2=2y
(h,k)=(0,0)
vertex: (0,0)
4p=2
p=1/2
focus: (0,1/2)
directrix: y=-1/2
RELATED QUESTIONS
Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3,TimothyLamb)
parabola,x^2 +6x -y +11 =0
find the vertex,focus and directrix of the... (answered by lwsshak3)
Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3)
Find the vertex, focus and directrix of the parabola ( x -5 )^2 = 8... (answered by josgarithmetic)
Find the vertex, focus, and directrix of the parabola... (answered by Mathtut)
Find the vertex, focus, directrix, and focal width of the parabola.
-1/40 x^2=... (answered by josgarithmetic)
Find the vertex, focus, and directrix of the parabola with equation... (answered by Edwin McCravy)
Find the focus, vertex and directrix of the parabola... (answered by ikleyn)
Find vertex, focus, and directrix of the parabola. 1/2y^2... (answered by lwsshak3)