SOLUTION: Find the equation of the circle of radius 8 with its center at the origin.

Question 553687: Find the equation of the circle of radius 8 with its center at the origin.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
formula for circle is (x-h)^2 + (y-k)^ = r^2
center is at the origin so (h,k) = (0,0)
r^2 = 8^2 = 64
equation is x^2 + y^2 = 64
to graph the circle, solve for y.
subtract x^2 from both sides of the equation to get:
y^2 = 64 - x^2
take the square root of both sides of the equation to get:
y = +/- sqrt(64-x^2)
graph looks like this:

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