SOLUTION: An object is fired upward from the top of a tower at the velocity of 80 feet per second. the tower is 200 feet high. the height of the object above the ground t seconds after firin

Question 551776: An object is fired upward from the top of a tower at the velocity of 80 feet per second. the tower is 200 feet high. the height of the object above the ground t seconds after firing is given by the formula h(t)=-16t^2 +80t+200.
a) What is the maximum height reached by the object?
b) How long after firing does it reach maximum height?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
An object is fired upward from the top of a tower at the velocity of 80 feet per second. the tower is 200 feet high. the height of the object above the ground t seconds after firing is given by the formula h(t)=-16t^2 +80t+200.
a) What is the maximum height reached by the object?
b) How long after firing does it reach maximum height?
**
h(t)=-16t^2 +80t+200.
complete the square
h(t)=-16(t^2-5t+25/4)+200+100
h(t)=-16(t-5/2)^2+300
ans:
maximum height reached by the object=300 ft
How long after firing does it reach maximum height=2.5 sec
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